Math, asked by Anonymous, 1 year ago


 \frac{1}{ \sqrt{x} }  + 2 = 0 \\  \\ find \: the \: value \: of \: x.

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Answers

Answered by Pikaachu
4
Heya

✓✓ The Square Root, whenever written, always expresses the Positive Result, and so, the sum of two positives can never add up to Zero !

 \frac{1}{ \sqrt{x} } + 2 = 0

 = > \sqrt{x} = - \frac{ 1}{2}

But this implies Positive = Negative :(

So indeed, the Question Has No solution !

____________________

Someone seems to be lacking the knowledge ^^"

Well, there's these

( i ) Square Roots

( ii ) x^( 1 / 2 ) types :

 4^{ \frac{1}{ 2 } } = x

and another way of Writing Equations ->

( iii )

 x^{2} = 4

! Caution : The third one can always except the answer ( -2 ) but however, the first and the second would never have "x" as Negative Real Numbers

-> The reason being, the first and second are called Primitive Roots and they always represent the Positive Root !

One can argue that [ ( -2 )^2 = 4 ] but conversely, [ √( 4 ) = -2 ] is wrong !

So, I request you please give a thought
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