![\frac{1}{ \sqrt{x} } + 2 = 0 \\ \\ find \: the \: value \: of \: x. \frac{1}{ \sqrt{x} } + 2 = 0 \\ \\ find \: the \: value \: of \: x.](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B+%5Csqrt%7Bx%7D+%7D++%2B+2+%3D+0+%5C%5C++%5C%5C+find+%5C%3A+the+%5C%3A+value+%5C%3A+of+%5C%3A+x.)
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Heya
✓✓ The Square Root, whenever written, always expresses the Positive Result, and so, the sum of two positives can never add up to Zero !
![\frac{1}{ \sqrt{x} } + 2 = 0 \frac{1}{ \sqrt{x} } + 2 = 0](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B+%5Csqrt%7Bx%7D+%7D+%2B+2+%3D+0)
![= > \sqrt{x} = - \frac{ 1}{2} = > \sqrt{x} = - \frac{ 1}{2}](https://tex.z-dn.net/?f=+%3D+%26gt%3B+%5Csqrt%7Bx%7D+%3D+-+%5Cfrac%7B+1%7D%7B2%7D+)
But this implies Positive = Negative :(
So indeed, the Question Has No solution !
____________________
Someone seems to be lacking the knowledge ^^"
Well, there's these
( i ) Square Roots
( ii ) x^( 1 / 2 ) types :
![4^{ \frac{1}{ 2 } } = x 4^{ \frac{1}{ 2 } } = x](https://tex.z-dn.net/?f=+4%5E%7B+%5Cfrac%7B1%7D%7B+2+%7D+%7D+%3D+x++)
and another way of Writing Equations ->
( iii )
![x^{2} = 4 x^{2} = 4](https://tex.z-dn.net/?f=+x%5E%7B2%7D+%3D+4)
! Caution : The third one can always except the answer ( -2 ) but however, the first and the second would never have "x" as Negative Real Numbers
-> The reason being, the first and second are called Primitive Roots and they always represent the Positive Root !
One can argue that [ ( -2 )^2 = 4 ] but conversely, [ √( 4 ) = -2 ] is wrong !
So, I request you please give a thought
✓✓ The Square Root, whenever written, always expresses the Positive Result, and so, the sum of two positives can never add up to Zero !
But this implies Positive = Negative :(
So indeed, the Question Has No solution !
____________________
Someone seems to be lacking the knowledge ^^"
Well, there's these
( i ) Square Roots
( ii ) x^( 1 / 2 ) types :
and another way of Writing Equations ->
( iii )
! Caution : The third one can always except the answer ( -2 ) but however, the first and the second would never have "x" as Negative Real Numbers
-> The reason being, the first and second are called Primitive Roots and they always represent the Positive Root !
One can argue that [ ( -2 )^2 = 4 ] but conversely, [ √( 4 ) = -2 ] is wrong !
So, I request you please give a thought
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