Question

$\frac{1}{ \sqrt{x {}^{2} } + x + 1}$
differentiate it​

Answer 1

Answer:

$\frac{1}{ \sqrt{ {x}^{2} } + x + 1} \\ = \frac{1}{ \sqrt{x \times x} + x + 1 } \\ = \frac{1}{x + x + 1} \\ = \frac{1}{2x + 1} \\ 2x + 1 = 1 \\ 2x = 1 - 1 \\ x = 0$