Math, asked by amalfatema2004, 4 months ago

$\frac{1 + \tanᎾ }{ \secᎾ} - \frac{ \secᎾ}{1 + \tanᎾ} = \frac{2 \sinᎾ \: \cos Ꮎ}{ \sinᎾ + \cosᎾ}$

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Answered by syad2345

0

Answer:

sorry dont know i

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