Math, asked by amalfatema2004, 3 months ago


 \frac{1 +  \tanᎾ }{ \secᎾ}  -  \frac{ \secᎾ}{1 +  \tanᎾ}  =  \frac{2 \sinᎾ \:  \cos Ꮎ}{ \sinᎾ +  \cosᎾ}

Answers

Answered by syad2345
0

Answer:

sorry dont know i

Step-by-step explanation:

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