Question

$\frac{1+tan60}{1-tan60}$

Answer 1

${\underline{\huge{\mathbf{\color{maroon}{heya\:dost}}}}}$

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Question :-

$\frac{1+tan60}{1-tan60}$

Step by step solution :-

${\underline{\huge{\mathbf{\color{red}{tan 60 = \sqrt 3}}}}}$

• putting value of tan 60 in question

$\frac{1+tan60}{1-tan60}$

$\frac{1+\sqrt 3}{1-\sqrt 3}$

• rationalizing the denominator

$\frac{1+\sqrt 3}{1-\sqrt 3}$ * $\frac{1+\sqrt 3}{1+\sqrt 3}$

$\frac{(1+\sqrt3)^2}{1^2-\sqrt3^2}$

• $(a+b)^2 = a^2 +b^2 + 2ab$
• $(a+b)(a-b)= a^2 - b^2$

$\frac{1^2 + \sqrt 3^2 + 2*1*\sqrt 3}{1-9}$

$\frac{1 + 3 + 2\sqrt 3}{-8}$

$\frac{4+2\sqrt 3}{-8}$

$\frac{2(2+\sqrt 3)}{-8}$

$\frac{2+\sqrt 3}{-4}$

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${\underline{\huge{\mathbf{\color{maroon}{thank\:you}}}}}$