Question

$\frac{1}{x - 1} + \frac{2}{x - 2} = \frac{3}{x - 3}$
answer isnt 3/7
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Answer 1

Question:-

$\frac{1}{x - 1} + \frac{2}{x - 2} = \frac{3}{x - 3}$

Answer:-

$\frac{1}{x - 1} + \frac{2}{x - 2} = \frac{3}{x - 3} \\ \frac{x - 2 + 2(x - 1)}{(x - 1)(x - 2) } = \frac{3}{x - 3} \\ \frac{2x + x - 2 - 2}{(x - 1)(x - 2)} = \frac{3}{x - 3} \\ (x - 3)(3x - 4) = 3(x - 1)(x - 2) \\ {3x}^{2} - 13x + 12 = {3}( {x}^{2} - 3x + 2) \\ {3x}^{2} - 13x + 12 = {3x}^{2} - 9x + 6 \\ - 13x + 12 = - 9x + 6 \\ 13x - 12 = 9x - 6 \\ 13x - 9x = 12 - 6 \\ 4x = 6 \\ x = \frac{6}{4} \\ x = \frac{3}{2} .$