Question

$\frac{1}{ {x}^{2} } + 3x - 4$
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Answer 1

Answer:

✅Here's your answer

$\frac{1}{ {x}^{2} } + 3x - 4 = 0 \\ \\ \frac{1 + 3 {x}^{3} - 4 {x}^{2} }{ {x}^{2} } = 0 \\ \\ \\ 3 {x}^{3} - 4 {x}^{2} + 1 = 0 \\ \\ x(3 {x}^{2} - 4x + 1) = 0$

$x(3 {x}^{2} - 3x - x + 1) = 0 \\ \\ x(3x(x - 1) - 1(x - 1)) = 0 \\ \\ x(3x - 1)(x - 1) = 0 \\ \\ (3x - 1)(x - 1) = 0$

Hope it helps ✌