Question

$\frac{1}{x} + \frac{1}{3y} = \frac{1}{6} \\ \frac{3}{x} + \frac{2}{y} = 0 \:$
$x \: or \: y \: k \: liya \: hal \: kro$

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Answer 1

Answer:

Step-by-step explanation:

take 1/x = v

take 1/y = u

v + 1/3 u = 1/6

3v + 2u = 0

solve them to get x and y

3v + 1u / 3 = 1/6

3v + 1u = 1/2 -------------(1)

3v + 2u = 0 --------------(2)

by elimination method

-u = 1/2 - 0

-u = 1/2

u  = -1/2

y = -2

substitute value of u in (2)

3v + 2(-1/2) = 0

3v - 1 = 0

3v = 1

v = 1/3

x = 3

hence the value of x = 3

y = -2

Answer 2

Step-by-step explanation:

SOLUTION ✍️

_____________________

Step-by-step explanation:

take 1/x = v

take 1/y = u

v + 1/3 u = 1/6

3v + 2u = 0

• solve them to get x and y

3v + 1u / 3 = 1/6

3v + 1u = 1/2 -------------(1)

3v + 2u = 0 --------------(2)

• by elimination method

-u = 1/2 - 0

-u = 1/2

u  = -1/2

y = -2

• substitute value of u in (2)

3v + 2(-1/2) = 0

3v - 1 = 0

3v = 1

v = 1/3

x = 3

hence the value of x = 3

y = -2

Hope this helps you!!