Question

$\frac{1}{y + 2} + \frac{4}{y - 3}$
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Answer 1

Answer:

$\frac{1}{y + 2} + \frac{4}{y - 3} \\ by \: taking \: lcm; \\ \\ \frac{y - 3 + 4y + 8}{(y + 2)(y - 3)} \\ = > \frac{5y + 5}{ {y}^{2} - 3y + 2y - 6} \\ = > \frac{5y + 5}{ {y}^{2} - y - 6}$