Question

$\frac{13}{2} + \frac{3}{2} (1 - 2x) = 4 \: find \: the \: value \: of \: x \: step \: by \: step \:$
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Answer 1

Step-by-step explanation:

= 16/2 (1-2x) = 4

= 8(1-2x) = 4

= 8-16x = 4

= 16 X = 4-8

16x=-4

= X = -4/16

= X = -1/4

hope it helps

Answer 2

Given:-

$\implies \sf \dfrac{13}{2} + \dfrac{3}{2} (1-2x)=4$

To find:-

$\implies \sf The \: value \: of \:x$

Solution:-

$\implies \sf \dfrac{13}{2} + \dfrac{3}{2} (1-2x) = 4 \\ \\ \implies \sf \dfrac{13}{2} - \dfrac{6x - 3}{2} = 4 \\ \\ \implies \sf \dfrac{16 - 6x}{2} = 4 \\ \\ \implies \sf \dfrac{-6x + 16}{2} = 4 \\ \\ \implies \sf -6x + 16 = 8 \\ \\ \implies \sf 6x = 8 \\ \\ \implies \sf x = \dfrac{8}{6} \\ \\ \implies \sf = \dfrac{4}{3}$

Answer:-

$\large {\boxed {\boxed {\sf {\red {= \dfrac{4}{3}} }}}}$

☃️ Finally we are done with the answer..