Question

$\frac{16}{ \sqrt{41} - 5 }$
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Answer 1

Step-by-step explanation:

$\frac{16}{ \sqrt{41} - 5} = \frac{16}{ \sqrt{41} - 5} \times \frac{ \sqrt{41} + 5 }{ \sqrt{41} + 5 } \\ = \frac{16( \sqrt{41} + 5)}{41 - 25} \\ = \frac{16 \sqrt{41} + 80}{16} \\ = \sqrt{41} + 80$