Math, asked by sudiptaroy409, 2 months ago


 \frac{19}{42}  \div ( \frac{2}{3}  - ( \frac{5}{7}  - (4 \times \frac{1}{2}  -  \frac{1}{3}  \div   \frac{1}{12} )))

Answers

Answered by Anonymous
8

Solution :-

19/42 (2/3-(5/7-(4*1/2-1/3/1/12 )))

The given question can be solved be using the rule of BODMAS

BODMASS stands for bracket open division, multiplication, Addition , Subtraction

Let's start

= 19/42 (2/3-( 5/7-( 4 * 1/2-1/3/1/12)))

= 19/42 (2/3-(5/7-(2 * 1-1/3 * 12/1)))

= 19/42 (2/3 - (5/7 - (2 - 4)))

= 19/42 (2/3 - ( 5/7 - ( -2 )))

= 19/42 ( 2/3 - ( 5/7 + 2 ))

= 19/42 ( 2/3 - ( 5 + 14/7 ))

= 19/42 ( 2/3 - 19/7 )

= 19/42 ( 14 - 57/21 )

= 19 /42 ( 43/21 )

= 19/42 * 43/ 21

= 817/882

= 0.926

0.926 is your answer mate .

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