Question

$( \frac{2}{3}^{2})^{3} \times (\frac{1}{3})^{ - 4} \times {3}^{ - 1} \times 6 ^{ - 1}$

Answer 1

$({ { \frac{2}{3} }^{2} })^{2} \times ({ \frac{1}{3} })^{ - 4} \times {3}^{ - 1} \times {6}^{ - 1} \\ = \frac{ {2}^{6} }{ {3}^{2} } \times {3}^{4} \times \frac{1}{3} \times \frac{1}{2} \times \frac{1}{3} \\ = {2}^{6 - 1} \times {3}^{4 - 2 - 1 - 1 } \\ = {2}^{5} \times {3}^{0} \\ = 32 \times 1 \\ = 32$