Math, asked by Mahi856, 4 months ago


 \frac{2}{3} {x}^{2}  -  \frac{1}{3}x = 1
Solve the above equation by Factorisation

Answers

Answered by ITZBFF
24

 \mathsf \red{Question :  \: } \mathcal{ \frac{2}{3}  {x}^{2}  -  \frac{1}{3} x = 1} \\  \\  \mathsf{ \frac{2 {x }^{2}  - 1x}{3}  = 1} \\  \\  \mathsf{2 {x}^{2}  - x = 3} \\  \\  \mathsf{2 {x}^{2} - x - 3 = 0 } \\  \\  \mathsf{2 {x}^{2} + 2x - 3x - 3 =  0} \\  \\  \mathsf{2x(x + 1) - 3(x + 1) = 0} \\  \\  \mathsf{(x + 1).(2x - 3) = 0} \\  \\  \mathsf{x + 1 = 0    \:  \:  \:  \: |  \:  \: 2x - 3 = 0} \\  \\  \mathsf{x =  - 1 \:  \:   \:  \:  \: |  \:  \:  \: x =  \frac{3}{2} } \\

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