Question

$\frac{2(3x - 1) - (2x + 1)}{7x - 2} = \frac{1}{2}$
pls solve this and get 60 points​

Answer 1

$\dfrac{2(3x \:- \:1) \:-\: (2x \:+\: 1)}{7x - 2} \:= \:\dfrac{1}{2}$

____________ [ GIVEN ]

• We have to find the value of x.

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=> $\dfrac{2(3x \:- \:1) \:-\: (2x \:+\: 1)}{7x - 2} \:= \:\dfrac{1}{2}$

=> $\dfrac{6x \:-\: 2 \:-\: 2x \:+\: 1}{7x\: - \:2} \:= \:\dfrac{1}{2}$

=> $\dfrac{4x \:-\: 1}{7x \:-\: 2} \:= \:\dfrac{1}{2}$

Cross multiply them

=> 2(4x - 1) = 7x - 2

=> 8x - 2 = 7x - 2

=> 8x - 7x = - 2 + 2

=> x = 0

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x = 0

_____________ [ ANSWER ]

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☆ VERIFICATION :

From above calculations we have x = 0

Put value if x in this : $\frac{2(3x \:- \:1) \:-\: (2x \:+\: 1)}{7x - 2} \:= \:\frac{1}{2}$

=> $\frac{2(3(x \:- \:1) \:-\: (2x \:+\: 1)}{7x - 2} \:= \:\frac{1}{2}$

=> $\frac{6(0)\:-\: 2 \:-\: 2(0) \:+\: 1}{7(0)\: - \:2} \:= \:\frac{1}{2}$

=> $\frac{-\: 2 \:+\: 1}{ - \:2} \:= \:\frac{1}{2}$

=> $\frac{-\: 1}{ - \:2} \:= \:\frac{1}{2}$

=> $\frac{ 1}{ 2} \:= \:\frac{1}{2}$

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Answer 2

{2(3x -1) - (2x +1)}/(7x -2)= 1/2

(6x -2 -2x -1)/(7x -2)=1/2

4x -3 =( 7x -2)/2

8x -6=7x -2

x = 4