Question

$\frac{2}{ \sqrt{5} + \sqrt{3 } + 2 }$
solve it I'll mark as the brainliest.​

Answer 1

Answer:

$\frac{2}{ \sqrt{5 } + \sqrt{3} + 2} = \frac{2}{ \sqrt{5} + \sqrt{3} + 2 } \times \frac{ \sqrt{5} + \sqrt{3} - 2 }{ \sqrt{5} + \sqrt{3} - 2 } \\ \\ \frac{2( \sqrt{5} + \sqrt{3} - 2) }{( \sqrt{5} + \sqrt{3 }) ^{2} - 4 } = \frac{2( \sqrt{5} + \sqrt{3} - 2) }{2 + \sqrt{15} } \\ \\ = ( 2\sqrt{5} - \sqrt{75} + 2 \sqrt{3} - \sqrt{45} - 4 + 2 \sqrt{15} ) \div - 11 \\ \\ = \frac{ - \sqrt{5} - 3 \sqrt{3} - 4 + 2 \sqrt{15} }{11} \\ \\ i \: hope \: this \: help \: you \: mark \: \\ it\: as \: brainliest \: and \: follow \: me$

Answer 2

Answer:

The answer is

$\frac{ \sqrt{5} - 3 \sqrt{3} - 4 + \sqrt{15} }{11}$