Question

$\frac{ {2}^{x - 1} \times {4}^{2x + 1} } { {8}^{x - 1} } = 64 \: find \: the \: x \: value$
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Answer 1

Answer:

right):\quad x=2,\:x=-4$ Solve x 2−6 x =8(1− x ): x =2, x =−4. $x=2,\:x=-4$ x =2, x =−4 ...

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$\frac{4\cdot\left(5^2\right)^5\left(-20\right)^3\left(-8\ right)^{-6}}{5^{-3}\cdot\:25^3\left(\left(-5\ ... $=-\frac{\ frac{9765625}{1024}}{5^8}$=−97656251024 5 8 ...

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