Question

$\frac{2x + 1}{3} + 1 = \frac{7x - 3}{2}$
pls solve and check​

Answer 1

Answer:

x= 1

Step-by-step explanation:

$\frac{2x + 1}{3} + 1 = \frac{7x - 3}{2}$

$\frac{2x + 1}{3} - \frac{7x - 3}{2} = - 1$

$\frac{2(2x + 1) - 3(7x - 3)}{6} = - 1$

$\frac{4x + 2 - 21x + 9}{6} = - 1$

$= - 17x + 11 = - 1 \times 6$

$= - 17x = - 6 - 11$

$- 17x = -17$

$x = \frac{ -17}{-17}$

x = 1