Math, asked by satyajeetprasad657, 1 year ago

$\frac{2x - 1}{3} - \frac{6x - 2}{5} = \frac{1}{3}$

Answers

Answered by Anonymous

41

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Step-by-step explanation:

$Given : Expression \frac{2x-1}{3}-\frac{6x-2}{5}=\frac{1}{3}$

To find : Solve the expression ?

Solution :

$Expression \frac{2x-1}{3}-\frac{6x-2}{5}=\frac{1}{3}$

Taking LCM,

$\frac{5(2x-1)-3(6x-2)}{15}=\frac{1}{3}$

$\frac{10x-5-18x+6}{15}=\frac{1}{3}</p><p>\frac{1-8x}{15}=\frac{1}{3}$

Cross multiply,

3(1-8x)=15

3-24x=15

24x=-12

$x=-\frac{12}{24}</p><p>x=-\frac{1}{2}$

$Therefore, The value of x is x=-\frac{1}{2}$

Answered by Anonymous

2

Answer

Here we need to find the value of variable 'x'

As per your question,

$\frac{2x - 1}{3} - \frac{6x - 2}{5} = \frac{1}{3}$

Firstly we need to have a same denominator before we can add up two fraction.

Taking LCM = 15

We get,

$\implies \rm \frac { 5(2x - 1 ) - 3(6x - 2 )} { 15 } = \frac { 1 } { 3 }$

$\implies \rm \frac { 10x - 5 - 18x + 6 } { 15 } = \frac { 1 } { 3 }$

$\implies \rm \frac { -8x + 1 } { 15 } = \frac { 1 } { 3 }$

Cross multiplying it,

$\implies \rm -24x + 3 = 15$

$\implies \rm -24x = 12$

$\implies \rm x = \frac { -1 } { 2 }$

We got our value of x = $\rm \frac { -1 } { 2 }$

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