![\frac{2x + 2}{2} - \frac{4x - 8}{3} = 0 \frac{2x + 2}{2} - \frac{4x - 8}{3} = 0](https://tex.z-dn.net/?f=+%5Cfrac%7B2x+%2B+2%7D%7B2%7D++-++%5Cfrac%7B4x+-+8%7D%7B3%7D++%3D+0)
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3(2x+2)/6-(4x-8)/6=0
(6x+6-(8x-16))/6=0
6x+6-8x+16=0*6
-2x=-22
x=11
Hope it helps
(6x+6-(8x-16))/6=0
6x+6-8x+16=0*6
-2x=-22
x=11
Hope it helps
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