Question

$\frac{2x - 3}{4x - 5} = \frac{4}{7}$
solve this linear equation.useful answers will be marked as brainliest.useless answers will be reported.​

Answer 1

Given:

$\dfrac{2x-3}{4x-5} = \dfrac{4}{7}$

To Find:

The value of x.

Solution:

$\dfrac{2x-3}{4x-5} = \dfrac{4}{7}$

Using cross multiplication,

⇒ 7(2x - 3) = 4(4x - 5)

Solve the brackets,

⇒ 14x - 21 = 16x - 20

Take numbers to RHS and variable to LHS,

⇒ -21 + 20 = 16x - 14x

Solve the terms,

⇒ -1 = 2x

Take 2 to LHS,

⇒ $\dfrac{-1}{2} = x$

∴ Thus the value of x is $\dfrac{-1}{2}$.

Answer 2

Answer:

• $\tt x= \dfrac{-1}{2}$

Step-by-step explanation:

Question

• $\dfrac{2x - 3}{4x - 5} = \dfrac{4}{7}$

Solution

• $\dfrac{2x - 3}{4x - 5} = \dfrac{4}{7}$

• $\mathfrak {Do\:Cross\:Multiplication}$

• $\tt 7 (2x - 3 ) = 4(4x - 5 )$

• $\tt 14x - 21 = 16x - 20$

• $\tt 14x - 16x = 21 - 20$

• $\tt 2x = -1$

• Note :- If we are bringing any term to LHS or RHS its sign will change.. Eg. If an number's sign is + in L.H.S when we will bring it to the right side it sign will change to -.

• $\tt x= \dfrac{-1}{2}$