Question

$\frac{2x - 5}{3} + \frac{3x - 2}{2} = 1$
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Answer 1

$\huge{\bold{\pink{\mathfrak{Answer:}}}}$

$\frac{2x - 5}{3} + \frac{3x - 2}{2} = 1$

$2(2x-5)+3(3x-2)=1$

$4x-10+9x-6=1$

$13x-16=1$

$13x=17$

$x= \frac{\cancel{17}}{\cancel{13}}$

$\boxed{\boxed{\pink{x=1.307}}}$

Answer 2

$\huge \underline \red{answer}$

$[tex] \huge \underline \bold \red{given}$

$\bold{ \frac{2x - 5}{3} + \frac{3x - 2}{2} = 1}$

$\huge \underline \bold \green{lcm \: of \: 3 \: and \: 2}$

$\huge \underline \bold \blue {6}$

$\huge \underline{so \: that}$

$\huge \red{ \frac{2(2x - 5 )+3( 3x - 2)}{6} = 1}$

$\huge \bold { \frac{4x - 10 + 9x - 6}{6} = 1}$

$\huge \bold { \frac{5x - 16}{6} = 1}$

$\huge \bold{5x - 16} = 6$

$\huge \bold {5x = 6 + 16}$

$\huge \bold{5x = 22}$

$\huge \: x = \frac{22}{5}$

$\huge \bold \purple{4.4}$

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