Question

$\frac{(2x + 9)2}{2(2x + 3} = \frac{4}{3}$
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Answer 1

Answer:

$\frac{(2x + 9) {2}^{2} } {2(2x + 3)} = \frac{4}{3} \\ \frac{(2x + 9) 4 } {2(2x + 3)} = \frac{4}{3} \\ \frac{(2x + 9) {2} } {(2x + 3)} = \frac{4}{3} \\ \frac{(4x + 18) } {(2x + 3)} = \frac{4}{3} \\3 (4x + 18) =4 (2x + 3) \\ 12x + 54=8x + 12\\ 12x - 8x = - 54 + 12 \\ 4x = - 42 \\ x = \frac{ - 42}{4} \\ x= - 10.5$