Question

$\frac{2x}{x - 4} + \frac{2x - 5}{x - 3} = \frac{25}{3}$
solve by factorisation method pls urgently

Answer 1

$\frac{2x}{x-4} + \frac{2x-5}{x-3} = \frac{25}{3}$

On cross-multiplication, we get

$\frac{2x(x - 3) + (2x - 5)(x - 4)}{(x - 4)(x - 3)} = \frac{25}{3}$

$\frac{2x^2 - 6x + 2x^2 - 8x - 5x + 20 }{x^2 - 7x + 12} = \frac{25}{3}$

$\frac{4x^2 - 19x + 20 }{x^2 - 7x + 12} = \frac{25}{3}$

3(4x^2 - 19x + 20) = 25(x^2 - 7x + 12)

12x^2 - 57x + 60 = 25x^2 - 175x + 300

13x^2 - 118x + 240 = 0

13x^2 - 78x - 40x + 240 = 0

13x(x - 6) - 40(x - 6) = 0

(13x - 40)(x - 6) = 0

x = 40/13, x = 6.


Hope this helps!

Answer 2

hey here is your answer.

your answer is

X = "6" or X = 3.07="40/13"

I hope it will help you..