Math, asked by seemakabra7, 6 months ago


 \frac{2y + 8}{3} - (y - 2)

Answers

Answered by chanchal20658
1

Answer:

 \frac{2y + 8}{3}  - (y - 2) \\  \frac{2y + 8}{3}  -  \frac{3y - 6}{3}  \\  \frac{2y + 8 - 3y + 6}{3} \\  \frac{ - y + 14}{3}

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