Question

$\frac{3}{4} (7x - 1) - (2x \ - \frac{1 - x}{2} ) = x + \frac{3}{2}$
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Answer 1

Question:-

Solve for x :-

$\sf{ \frac{3}{4} (7x - 1) - (2x \ - \frac{1 - x}{2} ) = x + \frac{3}{2} }$

Required Answer:-

Given Equation:-

$\\ \sf{\rightarrow{ \frac{3}{4} (7x - 1) - (2x \ - \frac{1 - x}{2} ) = x + \frac{3}{2} }}$

To Find:-

$\\ \sf{\rightarrow{The \: value \: of \: \bold{x}}}$

Solution:-

$\\ \sf{\bold{ \frac{3}{4} (7x - 1) - (2x \ - \frac{1 - x}{2} ) = x + \frac{3}{2} }}$

$\\ \sf{\implies{ \frac{21x - 3}{4} - \{ \frac{4x}{2} - \frac{(1 - x)}{2}\} = \frac{2x + 3}{4}}}$

$\\ \sf{\implies{ \frac{2x - 3}{4} - ( \frac{4x - 1 + x}{2} )} =\frac{2x + 3}{4} }$

$\\\sf{\implies{ \frac{21x - 3}{4} - \frac{5x - 1}{2} = \frac{2x + 3}{4} }}$

$\\\sf{\implies{ \frac{21x - 3 - 10x + 2}{4} = \frac{2x + 3}{2} }}$

$\\\sf{\implies{ \frac{11x - 1}{4} = \frac{2x + 3}{2} }}$

$\\ \sf{\implies{22x - 2 = 8x + 12}}$

$\\\sf{\implies{22x - 8x = 12 + 2}}$

$\\ \sf{\implies{14x = 14}}$

$\\ \sf{\implies{x = \frac{14}{14} }}$

$\\ \sf{\therefore{x = \red{\bold{1}}}}$

$\\ \\ \underline{\boxed{\rm{\green{Hence, \: the \: value \: of \: \bold{x} \: = \bold{1}}}}}$