Question

$( \frac{3}{4} )^{x - 1} = \frac{9}{16}$
please solve the part b ​

Answer 1

$\LARGE{\underline{\underline{\pink{\sf{Required \: Answer:–}}}}}$

$\implies ( \frac{3}{4} )^{x - 1} = \frac{9}{16}$

$\implies ( \frac{3}{4})^{x - 1} = ( \frac{3}{4} )^{2}$

When Bases are same Exponents are also same at that case.

So,

$\implies x - 1 = 2$

$\implies x = 3$

HØPÈ ÏT HÊLPS ♠♦♠