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It has been given that,
⇒ ∠A=∠B−40
o
....(1)
∠A=∠C−50
o
....(2)
Now, in triangle ABC,
∠A+∠B+∠C=180
o
⇒ ∠A+∠A+40
o
+∠A+50
o
=180
o
⇒ 3∠A=180
o
−50
o
−40
o
⇒ 3∠A=90
o
⇒ ∠A=30
o
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I have almost finished the worksheet except for maths
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