Question

$( \frac{3}{5} x {}^{ {}^{2} }y) \times ( - \frac{15}{4} xy {}^{2} ) \times ( \frac{7}{9} x {}^{2} y {}^{2} )$
evaluate it for x=2 and y=-1

Answer 1

Hi there!

[ refer the attachment. ]

Hope it helps! :)

Answer 2

Heya ✋

Let see your answer !!!!

(3/5 x^2 y) × (- 15/4 x y^2) × (7/9 x^2 y)

= [3/5 × 2^2 × (-1)] × [-15/4 × 2 × (-1)^2] × [7/9 × 2^2 × (-1)]

= [3/5 × 4 × (-1)] × [-15/4 × 2 × (-1)] × [7/9 × 4 × (-1)]

= -12/5 × 15/2 × (-28)/9

= 56

Thanks :))))