Question

$\frac{3 \sqrt{12 } + 3 \sqrt{6} } {6 - 3}$
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Answer 1

Answer:

$\frac{3 \sqrt{12 } + 3 \sqrt{6} }{6 - 3}$

$\frac{3 \sqrt{4 \times 3} + 3 \sqrt{6} }{3}$

$\frac{3 \times 2 \sqrt{3} + 3 \sqrt{6} }{3}$

$\frac{6 \sqrt{3} + 3 \sqrt{6} }{3}$

take 3 common

$(3) \frac{2 \sqrt{3} + \sqrt{6} }{3}$

$2 \sqrt{3} + \sqrt{6}$

take root 3 common

$( \sqrt{3} )(2 + \sqrt{2} )$