Question

$\frac{3 \sqrt{2 + 2} }{3 \sqrt{2 - 2} } = a - b \sqrt{2}$
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Answer 1

Answer:

HERE YOU GO!!

$\frac{3\sqrt{2+2} }{3\sqrt{2-2} } = a-b\sqrt{2}$

$\frac{3\sqrt{2+2}(3\sqrt{2+2)} }{14} = a-b\sqrt{2}$

$\frac{9\sqrt{(2+2)*2 }+6\sqrt{2+2} }{14} = a-b\sqrt{2}$

$\frac{9*2\sqrt{2}+6\sqrt{4} }{14} = a-b\sqrt{x\2}$

$\frac{9*2\sqrt{2}+6*2 }{14} = a-b\sqrt{2}$

$\frac{18\sqrt{2}+12 }{14} = a-b\sqrt{2}$

$\frac{2(9\sqrt{2}+6 }{14} = a-b\sqrt{2}$

$\frac{9\sqrt{2+6} }{7} =a-b\sqrt{2}$

$-a = -b\sqrt{2} -\frac{9\sqrt{2+6} }{7}$

$a = b\sqrt{2} +\frac{9\sqrt{2}+6 }{7}$

,b∈ℝ

HOPE THIS HELPS

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