Question

$\frac{3\sqrt{2} }{\sqrt{6-}\sqrt{3} } +\frac{2\sqrt{3} }{\sqrt{6}{+} {2} } } -\frac{4\sqrt{3} }{\sqrt{6-}{\sqrt{2} } }$

Answer 1

Answer:

3√2 / (√6 -√3) + 2√3 /( √6 +2 ) - 4√3/(√6 -√2)

multiplying the conjugate

=3√2 (√6 +√3) / 3 + 2√3 ( √6 -2 ) / 2 - 4√3 (√6 +√2)/ 4

opening the bracket

=(6 √3+ 3√6)/3 + (6√2 - 4√3)/2 - ( 12√2 +4√6 )/4

= 2√3 + √6 + 3√2 -2√3 - 3√2 -√6

= 0 ( answer )

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