Question

$\frac{3x - 2}{4} - \frac{2}{3} = \frac{2x + 3}{3} - x$
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Answer 1

$\mathfrak \blue{ \large{answer : }}$

$\tt \blue{here \: is \: your \: answer : }$

$\frac{3x - 2}{4} - \frac{2}{3} = \frac{2x + 3}{3} - x$

$\frac{3(3x - 2) - 8}{12} = \frac{2x + 3 - 3x}{3}$

$\frac{9x - 6 - 8}{12} = \frac{ 3 - x}{3}$

$\frac{9x - 14}{12} = \frac{3 - x}{3}$

$3(9x - 14) = 12(3 - x)$

$27x - 42 = 36 - 12x$

$27x + 12x = 36 + 42$

$39x = 78$

$x = \frac{78}{39}$

$\tt \red{x = 2}$