Question

$( \frac{4}{3} {x}^{2} yz) \times (\frac{1}{3} {y}^{2} 2x) \times ( - 6xy {z)}^{2}$
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Answer 1

Answer:

write your question in proper way

Step-by-step explanation:

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Answer 2

Answer:

$\boxed {32 x^5y^5z^3}$

Step-by-step explanation:

$(\frac{4}{3} x^{2} yz) \times (\frac{1}{3} y^{2}2x) \times (36x^{2} y^{2} z^{2} ) \\\\=> (4 \times 2 \times 4) \times (x^5y^5z^3)\\\\=> 32 x^5y^5z^3$

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