Math, asked by tapasdutta654, 6 months ago

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( \frac{4}{3} x {2}^{} yz) \times ( \frac{1}{3} y {2}^{} zx) \times ( - 6xyz {2}^{} )

Answers

Answered by Anonymous
2

Answer:

 \frac{4}{3} x2yz \times  \frac{1}{3} y2zx \times  - 6xyz2

 \frac{4}{3}  \times  \frac{1}{3} \times  - 6 \times x2yz \times y2zx \times xyz2

 \frac{ - 8}{3} ( 8{x}^{3}  {y}^{3}  {z}^{3)}

 \frac{ - 64}{3}  {x}^{3}  {y}^{3}  {z}^{3}

Step-by-step explanation:

HOPE YOU GOT IT.....

Answered by xainlone856
9

Answer:

hyyyy mate

Step-by-step explanation:

above is the right answer.....

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