Question

$\frac{4}{x + 1} + \frac{5}{x + 3} = \frac{9}{x + 2}$
solve each of the following equations ​

Answer 1

$\huge\boxed{\fcolorbox{white}{pink}{answer}}$

Here is ur answer mate

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$\frac{4}{x + 1} + \frac{5}{x + 3} = \frac{9}{x + 2} \\ \frac{4(x + 3) + 5(x + 1)}{(x + 1)(x + 3)} = \frac{9}{x + 2} \\ \frac{4x + 12 + 5x + 5}{x {}^{2} + 3x + x + 3} = \frac{9}{x + 2} \\ \frac{9x + 17}{x {}^{2} + 4x + 3} = \frac{9}{x + 2} \\ (9x + 17)(x + 2) = 9(x {}^{2} + 4x + 3) \\ 9x {}^{2} + 18x + 17x + 34 = 9x {}^{2} + 36x + 27 \\ 35x + 34 = 36x + 27 \\ 35x - 36x = 27 - 34 \\ - x = 7 \\ x = - 7$

$\huge\boxed{\fcolorbox{x=-7}{}{}}$

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Answer 2

Answer:

The last answer is correct...

Thank you❤