Question

$\frac { 4 x - 3 } { x + 3 } = 5$
please step by step solution and you brilliant ok ​

Answer 1

Corrected Question:

Solve the following equation -

• $\sf{\left[\dfrac{4x-3}{x+3}\right]=5}$

$\begin{gathered}\rule{230px}{.2ex}\\\end{gathered}$

Solution:

Here, we are given with an equation. We've been asked to solve it for x. To solve for x we've to bring all the variable to one side and all remaining values to the other side. Simplifying the values we'll get the final answer. Let's solve the given equation for x here.

$\dashrightarrow\quad\rm{\dfrac{4x-3}{x+3}=5}$

Now, firstly let's transpose the denominator from LHS to RHS. It's arithmetic operator will get changed.

$\dashrightarrow\quad\rm{4x-3=5\times (x+3)}$

Now, performing multiplication in RHS. To multiply, we will use distributive property. Distributive property is simply "multiplication distributes over addition" or in other words, the equation which is in the form a(b+c) can be written as ab + bc. This means the operand a is been distributed between the two other operand. So, using distributive property here, we get:

$\dashrightarrow\quad\rm{4x-3=5x+15}$

Now, let's bring the like terms to the one side of equation. This will help in solving the question further. Here, let's transpose 5x from RHS to LHS and -3 from LHS to RHS. It's sign will get changed.

$\dashrightarrow\quad\rm{4x-5x=15+3}$

Now, let's perform subtraction in LHS and addition in LHS to solve further.

$\dashrightarrow\quad\rm{-x=18}$

Now, as "x" cannot be negative so, in order to convert the negative x into positive we will multiply -1 to the whole equation. So, multiplying -1 in RHS and LHS.

$\dashrightarrow\quad\rm{-x\times -1=18\times -1}$

Now, let's perform multiplication in order to calculate the value of x.

$\dashrightarrow\quad\underline{\boxed{\pmb{\sf{\red{x=-18}}}}}\; \bigstar$

Therefore, the value of x is -18.