Question

$\frac{49 \times {2}^{ - 3} \times {5}^{4} }{ {8}^{ - 1} \times {7}^{2} \times 125}$
Simplify using laws of exponents ​

Answer 1

$\frac{49 \times {2}^{ - 3} \times {5}^{4} }{ {8}^{ - 1} \times {7}^{2} \times 125 } \\ = \frac{ {7}^{2} \times \frac{1}{2 {}^{3} } \times {5}^{4} }{ \frac{1}{ {2}^{3} } \times {7}^{2} \times {5}^{3} } \\ = {7}^{2 - 2} \times { \frac{1}{2} }^{3 - 3} \times {5}^{4 - 3} \\ = {7}^{0} \times { \frac{1}{2} }^{0} \times {5}^{1} \\ = 1 \times 1 \times 5 \\ = 5$

Hence 5 is the answer.