Question

$\frac{(4a^2-9b^2)^3+(9b^2-16c^2)^3+(16c^2-4a^2)^3}{(2a-3b)^3+(3b-4c)^3+(4c-2a)^3}$
plz solve this fast!!
first and correct solution will as marked as brainliest




for reference the answer is
$(2a + 3b)^3+(3b + 4c)^3+(4c + 2a)^3$
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Answer 1

Answer is given in the attachment.

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Answer 2

Answer:

The given question is solved correctly in the uploaded photo.

The answer given needs correction.There will be no cubes in each of the terms.