+b=
9a+b=21
find values of a and b
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Step-by-step explanation:
Hm… First use the roots to write the polynomial in factored form:
ax2+7x+b=0 , where x′=23 and x′′=−3
a(x−23)(x+3)=0
See why this is true? Then distribute the whole thing:
(ax+3a)(x−23)=0
ax2+(3−23)ax−2a=0
ax2+(7a3)x−2a=0
Here we get that
−2a=b
And
7a3=7
Solving that we have
a=737=3
And
b=−2(3)=−6
Voilá! Er… I mean… QED
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