Question

$\frac{4x}{3} + 3 = \frac{9x}{10}$
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Answer 1

Solution :-

→ 4x/3 + 3 = 9x/10

→ 9x/10 - 4x/3 = 3

→ 27x - 40x/30 = 3

→ -13x/30 = 3

→ - 13x = 90

→ x = -90/13

Hence,

• Required value of x is -90/13

Answer 2

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$\huge\underline \mathfrak\green{solution:-}$

$\frac{4x}{3} + 3 = \frac{9x}{10}$

$\frac{4x + 9}{3} = \frac{9x}{10}$

$40x + 90 = 27x$

$40x - 27x =-90$

$13x = -90$

$x = \frac{-90}{13}$

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