Question

$\frac{4z + 7}{9 - 3z} = \frac{1}{4}$
please solve this chapter name linear equation and class 8
answer = -1
I want step by step answer and don't spam please otherwise I will report your 5 answers
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Answer 1

Answer:

z=(-1)

Step-by-step explanation:

4z+7/9-3z=1/4

Cross multiply

4(4z+7)=1(9-3z)

16z+28=9-3z

16z+3z=9-28

19z=(-19)

z=(-19)/19

z=(-1)

Answer 2

Step-by-step explanation:

$\sf : \implies \frac{4z + 7}{9 - 3z} = \frac{1}{4} \\ \sf : \implies \: 4(4z + 7) = 9 - 3z\\ \sf : \implies 16z + 28 = 9 - 3z\\ \sf : \implies \: 16z + 3z = 9 - 28\\ \sf : \implies 19z = -19\\ \sf : \implies z = \frac{19}{19} \\ \sf : \implies z = -1 ans.$