Question

$( \frac{5}{3} )^{ - 2} \times ( \frac{5}{3} )^{ - 14} =( \frac{5}{3} )^{8x}$
find the value of x

Answer 1

$({ \frac{5}{3} })^{ - 2 - 14} = ({ \frac{5}{3} })^{8x} \\ - 16 = 8x \\ x = \frac{ - 16}{8} = - 2$

Answer 2

( 5 / 3 ) ^ ( - 2 ) × ( 5 / 3 ) ^ ( - 14 ) = ( 5 / 3 ) ^8x

In both side bases are equal, i. e. ( 5 / 3 )

So, their exponents will become equal.

( -2 ) + ( - 14) = 8x

-16 = 8x

x = - 16 / 8 = - 2

$<h3>x = - 2$