Math, asked by mckoc31, 9 months ago

\frac{5-x}{5} = \frac{x+3}{15}
somebody please do this one job

Answers

Answered by Anonymous
6

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  •  \frac{5 - x}{5}  =  \frac{x + 3}{15}

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 \frac{5 - x}{5}  =  \frac{x + 3}{15}  \\  \implies \: {5 - x} =  \frac{x + 3}{3}  \\  \implies \: 15 - 3x = x + 3 \\  \implies \: 15 - 3 = 3x + x \\  \implies \: 4x = 12 \\  \implies \: x =  \frac{12}{4}  \\  \implies \: x = 3

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How to solve this type of equations ?

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▪ Look for the common factor of the denominator on both sides and write it in it's simplest form.

Ex- if the eq is

\frac{x+1}{a}= \frac{x+4}{3a}

then it can be written as

\frac{x+1}{1}=\frac{x+4}{3}

(where a is any number)

Further crossmultiply to get solution.

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▪If there is no common factor then simply do cross multiplication.

Ex-

\frac{x+1}{a}=\frac{x+2}{b}

can be written as,

{xb+b=ax+2a}

(remember here a and b are digits or any number.)

Answered by rajputvishal887
0
Just Simplify and you’ll get the answer
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