Answers
Answered by
2
Given 50/x^2 - 2x^2/81
= 50 * 81 - (2x^2 - x^2)/81x^2
= 4050 - 2x^4/81x^2
Note: 4050 - 2x^4 can be written as -2(x^4 -2025)
-2(x^2+45)*(x^2-45).
So, 50/x^2 - 2x^2/81 = -2(x^2 + 45) * (x^2 -45)/81x^2.
Hope this helps!
= 50 * 81 - (2x^2 - x^2)/81x^2
= 4050 - 2x^4/81x^2
Note: 4050 - 2x^4 can be written as -2(x^4 -2025)
-2(x^2+45)*(x^2-45).
So, 50/x^2 - 2x^2/81 = -2(x^2 + 45) * (x^2 -45)/81x^2.
Hope this helps!
Assassins2ei:
THANKS but can u pls do the problem using a^2 - b^2 = (a-b)(a+b)..........
Similar questions