Question

$\frac{6y + 1}{3} + 1 = \frac{y - 3}{6}$
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Answer 1

Answer:

$\sf{\dfrac{6y+1}{3}+1=\dfrac{y-3}{6}}$

$\sf{\leadsto{6\times\dfrac{6y+1}{3}+6=y-3}}$

$\sf{\leadsto{2(6y+1)+6=y-3}}$

$\sf{\leadsto{12y+2+6=y-3}}$

$\sf{\leadsto{11y=-11}}$

$\sf{\leadsto{y=-1}}$

Answer 2

Answer:

answer for the given problem is given