Question

$\frac{6y + 1}{3} + 1 = \frac{y - 3}{6}$
​

Answer 1

Answer:

$y = ( - 1)$

Step-by-step explanation:

$\frac{6y + 1}{3} + 1 = \frac{y - 3}{6} \\ \frac{6y + 1 + 3}{3} = \frac{y - 3}{6} \\ \frac{6y + 4}{3} = \frac{y - 3}{6} \\Cross \: multiply \\ 6(6y + 4) = 3(y - 3) \\ 36y + 24 = 3y - 9 \\ 36y - 3y = ( - 9) - 24 \\ 33y = ( - 33) \\ y = \frac{( - 33)}{33} \\ y = ( - 1)$

Answer 2

Answer:

y = ( - 1)y=(−1)

Step-by-step explanation:

\begin{gathered} \frac{6y + 1}{3} + 1 = \frac{y - 3}{6} \\ \frac{6y + 1 + 3}{3} = \frac{y - 3}{6} \\ \frac{6y + 4}{3} = \frac{y - 3}{6} \\Cross \: multiply \\ 6(6y + 4) = 3(y - 3) \\ 36y + 24 = 3y - 9 \\ 36y - 3y = ( - 9) - 24 \\ 33y = ( - 33) \\ y = \frac{( - 33)}{33} \\ y = ( - 1)\end{gathered}

3

6y+1

+1=

6

y−3

3

6y+1+3

=

6

y−3

3

6y+4

=

6

y−3

Crossmultiply

6(6y+4)=3(y−3)

36y+24=3y−9

36y−3y=(−9)−24

33y=(−33)

y=

33

(−33)

y=(−1)