Question

$\frac{7}{2} + \frac{35}{6} \div \frac{14}{3} =$
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Answer 1

7/2 + 35/6 * 3/14

7/2 + 35/28

(98 + 35)/28

133/28

Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The answer is $4 \dfrac{3}{4}$

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

$\tt\implies\dfrac{7}{2} + \dfrac{35}{6} \div \dfrac{14}{3}$

First, division. The reciprocal of $\dfrac{14}{3}$

$\tt{\implies} \: \dfrac{7}{2} + \dfrac{35}{6} \times \dfrac{3}{14}$

Reduce 3 and 6

$\tt{\implies} \: \dfrac{7}{2} + \dfrac{35}{28}$

Convert them into like fractions

LCM of 2 and 28 = 28

$\tt{\implies} \: \dfrac{7 \times 14}{2 \times 14} + \dfrac{35}{28}$

$\tt{\implies} \: \dfrac{98}{28} + \dfrac{35}{28}$

$\tt{\implies} \: \dfrac{133}{28}$

Reduce it by 7

$\tt{\implies} \: \dfrac{19}{4}$

Convert it into mixed fraction

$\tt{\implies} \: 4 \dfrac{3}{4}$

$\therefore$ The answer is $4 \dfrac{3}{4}$