Question

$\frac{7 {}^{3} }{7 {}^{x - 2} } = 7 {}^{7}$
​

Answer 1

ANSWER.

• x = -2

SOLUTION.

Here, it's given that,

$\tt \longrightarrow \dfrac{ {7}^{3} }{ {7}^{x - 2} } = {7}^{7}$

We know that,

$\tt \mapsto \dfrac{ {x}^{a} }{ {x}^{b} } = {x}^{a - b}$

So,

$\tt \longrightarrow {7}^{3 - (x - 2)} = {7}^{7}$

$\tt \longrightarrow {7}^{3 -x + 2} = {7}^{7}$

$\tt \longrightarrow {7}^{5 - x} = {7}^{7}$

Comparing base, we get,

$\tt \longrightarrow 5 - x=7$

$\tt \longrightarrow x=5 - 7$

$\tt \longrightarrow x= - 2$

★ So, the value of x is -2.

Answer 2

Answer:

$ANSWER.</p><p></p><p>x = -2</p><p></p><p>SOLUTION.</p><p></p><p>Here, it's given that, </p><p>[tex] \tt \longrightarrow \dfrac{ {7}^{3} }{ {7}^{x - 2} } = {7}^{7}$

We know that,

$\tt \mapsto \dfrac{ {x}^{a} }{ {x}^{b} } = {x}^{a - b}$

So,

$\tt \longrightarrow {7}^{3 - (x - 2)} = {7}^{7}$

$\tt \longrightarrow {7}^{3 -x + 2} = {7}^{7}$

$\tt \longrightarrow {7}^{5 - x} = {7}^{7}$

Comparing base, we get,

$\tt \longrightarrow 5 - x=7$

$\tt \longrightarrow x=5 - 7$

$\tt \longrightarrow x= - 2$

★ So, the value of x is -2.[/tex]