Question

$\frac{7}{5} \sqrt[4]{1250} - \frac{2}{3} \sqrt[4]{32} - \frac{1}{7} \sqrt[4]{162}$
solve the question​

Answer 1

Step-by-step explanation:

Subtracting a fraction from a whole

Rewrite the whole as a fraction using t2 as the denominator :

t

t.t2

t =

1

t2

Equivalent fraction: The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Answer 2

Answer:

Answer:

Simplification of

3\sqrt{45}-\sqrt{125}+\sqrt{200}-\sqrt{50}345−125+200−50

=4\sqrt{5}+5\sqrt{2}45+52

Step-by-step explanation:

Simplification of

3\sqrt{45}-\sqrt{125}+\sqrt{200}-\sqrt{50}345−125+200−50

= \begin{gathered}3\sqrt{(3\times3)\times5}-\sqrt{(5\times5)\times5}\\+\sqrt{(10\times10)\times2}-\sqrt{(5\times5)\times2}\end{gathered}3(3×3)×5−(5×5)×5+(10×10)×2−(5×5)×2

=3\times3\sqrt{5}-5\sqrt{5}+10\sqrt{2}-5\sqrt{2}3×35−55+102−52

= 9\sqrt{5}-5\sqrt{5}+10\sqrt{2}-5\sqrt{2}95−55+102−52

=(9-5)\sqrt{5}+(10-5)\sqrt{2}(9−5)5+(10−5)2

= 4\sqrt{5}+5\sqrt{2}45+52

Therefore,

Simplification of

3\sqrt{45}-\sqrt{125}+\sqrt{200}-\sqrt{50}345−125+200−50

=4\sqrt{5}+5\sqrt{2}45+52

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Step-by-step explanation:

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