Question

$( \frac{9}{16} \times \frac{4}{12} ) + ( \frac{9}{16} \times \frac{ - 3}{9} )$
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Answer 1

$( \frac{9}{16} \times \frac{4}{12} ) + ( \frac{9}{16} \times \frac{ - 3}{9} )$

$\frac{9}{16} \times \frac{4}{12 } = \frac{3}{16}$

$\frac{9}{16} \times \frac{ - 3}{9} = \frac{ - 3}{16}$

$\frac{3}{16} + ( \frac{ - 3}{16} ) = \frac{3}{16} - \frac{3}{16} = 0$

hence ,

$( \frac{9}{16} \times \frac{4}{12} ) + ( \frac{9}{16} \times \frac{ - 3}{9} )$

= 0

hope it helps you

pls mark as brainlliest

Answer 2

$\frac{9}{16 } \times \frac{4}{12} + \frac{9}{16} \times \frac{ - 3}{9}$

$\frac{9}{16} \times \frac{4}{12} = \frac{3}{16}$

$\frac{9}{16} \times \frac{ - 3}{9} = \frac{ - 3}{16}$

$\frac{3}{16} - \frac{3}{16} = 0$

hence the answer is 0